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write an equation in slope-inyercept form for the line with slope -4 that contains the points(0,-3)
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Point-slope form: (y+3)=-4(x) y=-4x-3
slope intercept form of a line is y = m.x + c where m is the slope and c is the intercept of the line. now you know the slope (= -4). all you want to know is the intercept. Since point (0,-3) is in the line so the equation of line will satisfy for the given line i.e, -3 = -4 (0) + c => c = -3 now we have both slope and intercept, so the equation of line is y = -4x -3 give me medal, if i really helped you. :)
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