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If A is in Quadrant II and cos A= -3/4, find an exact value for sin 2A
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Recall sin 2A=2sinAcosA. Make your triangle in 2nd quad with Cos A=-3/4 and find sin A
I ended up with a decimal..
Exact value means basically not using a calculator, keeping square root as a number.
so what did you get for it?
Just put up your work for the problem and we would tell you where you are going wrong.
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2(radical 7/4)(-3/4)
The numbers are correct, just cancel, simplify, keeping sq rt 7
so -6 radical 7 over 16?
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