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\[\int\limits_{0}^{1}(3x^2+2)^3 xdx\]
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let u=3x^2+2
How do I evaluate that then?
du/dx=6x so du=6xdx or du/6=xdx
if x=1, then u=3(1)^2+2=3+2=5 upper limit if x=0, then u=3(0)^2+2=0+2=2 lower limit
\[\int\limits_{2}^{5}(1/6)*u^{3}du\]
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