Question

29g of copper pellets are removed from a 300 Celsius oven and immediately dropped into 100 mL of water at 22 Celcius in an insulated cup.

What will the new water temperature be?

Answer 1

Q = m*C*delta T
Qc = .029 * 390 * (200 - Tf)
Qw = .1 * 4200 * (Tf - 22)

Qc = Qw

.029 * 390 * (200 - Tf) = .1 * 4200 * (Tf - 22)

Tf = 26.66
2 sig figs
27 degrees C