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express as a single log 2/3logbase2 8 + 1/3 logbase2 3 - 2logbase2 4
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use log rules n*logx = log(x^n) logx +logy = log(x*y) logx -logy = log(x/y)
i know te rules, want to verify my work done
oh ok \[=\log_{2}\frac{8^{2/3}*3^{1/3}}{16}\rightarrow \log_{2}\frac{3^{1/3}}{4} \]
thanks
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