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Mathematics 14 Online
OpenStudy (anonymous):

Hey guys I don't remember how to do limits. Please help! Here's my question. limit x-> postivie infiniti of (x-1/2x)/(2x+1/6x)

OpenStudy (anonymous):

use L-hospital (sometimes called L-hopital) rule.

OpenStudy (anonymous):

1.5

OpenStudy (anonymous):

Thanks :)

OpenStudy (anonymous):

before you use L-h rule - need to have infinity/infinity or o/o... simplify: lim (x*2x - 1) *6x/(2x*(12x^2+1) = 3lim (2x^2-1)/(12x^2+1) = ... now take a derivatives....

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