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y= 7r + 4 , solve r , if y = 32 ? show your work
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First, plug 32 in the place of y, you get: \[32=7r+4 ... (1)\]
Can you rewrite your equation with r in terms of y? Then just plug in the y value you are given.
Now, you should try to isolate r in one side.
So to get rid of the 4, subtract 4 from both sides, you get: \[32-4=7r+4-4 \implies 28=7r\]
Now, divide both sides by 7, you get: \[{28 \over 7}={7r \over 7} \implies 4=r\] So r is equal to 4.
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