Question

how do u solve

(2-x+3x^2)(3+2x-x^2+2x^4)

Answer 1

whats your definition of solve?

Answer 2

to me; solve would be to distribute each term in the left thru the paranethesis and then comcine like terms

Answer 3

sorry Find the first three terms of the product in ascending powers

(2-x+3x^2)(3+2x-x^2+2x^4)

Answer 4

ascending eh...from little power to biggest...

Answer 5

yes

Answer 6

6 +4x -3x+9x^2-2x^2-2x^2...if I see it right :)

6 +x +5x^2

Answer 7

and I think i see others....hold that

Answer 8

3 +2x -x^2
* 2 -x +3x^2
--------------
9x^2+0+0
-3x-2x^2+0
6+4x-2x^2
-------------------
6 +x +5x^2.....yeah, that should be it

Answer 9

thanks you

Answer 10

can u help me with one more

Answer 11

i can try

Answer 12

and this time let me do it and you do it also and then we can compare ou answers to see if i got it

Answer 13

k

Answer 14

(1-2x^2-x^4)(4+x^2-2x^4)

Answer 15

i got mine :)

Answer 16

i got mine

Answer 17

so i got 4+9x^2+5x^6

Answer 18

4 - 6x^2 -8x^4 ??

Answer 19

is it right

Answer 20

the lowest powers are x^0; x^2 and x^4

Answer 21

4 - 7x^2 -8x^4 ...had a typo :)

4x^0 = 4

x^2 -8x^2 = 7x^2

-2x^4 -2x^2 -4x^4 = -8x^4

Answer 22

0k - got it

Answer 23

thanks