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The sum of two numbers is 72, and twice their difference is 24. What is the smaller of the two numbers?
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x+y=72 2(x-y)=24
one number = x another - y now, just read the problem... x+y=72 2(x-y)=24 solve the system for z & y - your numbers
I got 12 for x. Am I on the right track?
x+y=72 x-y=12 2x=72+12=84 so x=84/2=42
y=72-x x-(72-x)=12 x-72+x=12 2x=12+72 2x=84 x=42
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So, how would I find the other number? Plug it in?
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