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3 ------ 4x-8 --------- 6 ------- x^2-4
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multiply by the recipricol... then multiply accross
(2/(4x-8)) ((x^2-4)/6
x^2-4/2(4x-8)
(x^2-4)/(3 (4 x-8))
This problem can be re-written as follows: (3/4x-8) [(x^2-4)/6] = [3/4(x-2)] [(x-2) (x+2)/6] Do some cancellation and you get: (x+2)/8
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