Question

what is the domain and range of f(x)=(x-2)^3/4?

Answer 1

\[f(x)=\sqrt[3]{(x-2)^{4}}\]

Will any value of X break the rules of mathematics?

can (x-2)^4 ever be negative?

If not, can the cube root of (x-2)^4 be negative?

Answer 2

sorry its actually supposed to be f(x)= \[\sqrt{(x-2)^3}\] all divided by 4