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OpenStudy (anonymous):
f(x) = x^2+2x+1 find the vertex pairs and axis of symmetry
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OpenStudy (amistre64):
axis of symetry is -b/2a: -2/; x = -1
OpenStudy (amistre64):
the vertex is on that axis so its (-1,y) when we use x=-1 in the equation we get y=0 vertex = (-1,0)
OpenStudy (anonymous):
thank you :)
OpenStudy (amistre64):
youre welcome
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