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Mathematics 18 Online
OpenStudy (chase):

does anyone know how to solve (1+tanx)(tan2x)=2tan/1-tanx?

OpenStudy (anonymous):

{tan = (1/2)*tan2x-(1/2)*tan2x*tanx^2, tan2x = tan2x, tanx = tanx}

OpenStudy (anonymous):

sub tan2x for 2tanx/(1-tan^2x) then factor (1-tan^2x) to (1+tanx)(1-tanx) cross out then your good

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