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Mathematics 10 Online
OpenStudy (chase):

using the trig identities to solve tanx=1-cos2x/sin2x

OpenStudy (anonymous):

ok sub cos2x for (1-2sin^2x) on the top and cos2x for 2sinxcosx on the bottom the 1 will subtract out and leave you with 2sin^2x/2sinxcosx witch =tanx after you cross out the sinx top and bottom

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