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How do I find the derivative of: x(3x - 9)^3
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Do I distribute the x first?
=(3x-9)^3 +x*(3(3x-9)^2 *3)=(3x-9)^3 +9x(3x-9)^2
let me know if any questions... :)
Ok, so does it become.... 2x^2 - 79x^2 -729
after combining everything?
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