A charge q1 = +4.0nC experiences a force of 3*10^-5N to the east when placed in an electric field. If the charged is replaced by another, q2 = -12nC, what will be the magnitude and direction of the force on the charge at that position?

Question

anonymous · Answer

$$F=Eq$$
therefore force is proportional to charge.
$$F ^{'}=Fq ^{'}/q$$
where $$F=3*10^{-5},q=4nc  ,  q ^{'}=-12nc$$
$$F ^{'}=-9*10^{-5}N$$
-ve sign indicates force in west direction