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the function V(t)=$3250-325t is a depreciation function for a computer. what is the range of this function?
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i think I answer this one sometime ago,,, today
factor out 325 so v(t) = 325(10-t). Because t = time, and time must be positive, t can only be 0 or greater. Thus, your range has a maximum of 3250 and no minimum. so range is (-infinity, 3250]. hope that helps
A.0<t<10 B.0<V(t)<10 C.0<t<3250 D.0<V(t)<3250 (arrows are equal as in all underlined)
ok, the correct choice is D.
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