Question

how do i enter int (1,sqrt x) of (2t-1)/(t+2)dt

Answer 1

it would be\[\int\limits_{1}^{\sqrt{x}}\frac{2t-1}{t+2}dt\]
In the equation editor it would look like:
int_{1}^{sqrt{x}}frac{2t-1}{t+2}dt

Pretty complicated, right? :)