if f is one to one find an equation for its inverse
f(x)= 6/x-3 and f(x) = sqr(x+1) x -1

Question

if f is one to one find an equation for its inverse
f(x)= 6/x-3 and f(x) = sqr(x+1) x > -1

myininaya · Answer

the first f(x)=6/(x-3) or 6/x-3?

anonymous · Answer

first is  f(x) = 6/(x-3)

myininaya · Answer

ok so do you know how you would solve for x?

anonymous · Answer

solve for x, why do we need to solve for x, should we put (x-3)=0 ?

myininaya · Answer

no to find inverse all you have to do is solve for x
and when you get done doing this replace x with f^{-1}(x) and replace f(x)=y with x
ok y=6/(x-3) multiply both sides by x-3
y(x-3)=6
yx-3y=6
yx=6+3y
x=(6+3y)/y
f^{-1})(x)=(6+3x)/x

myininaya · Answer

2nd second one we have
y=sqrt(x+1)
square both sides
y^2=x+1
subtract 1
y^2-1=x
x=y^2-1
f^{-1}(x)=x^2-1

anonymous · Answer

thank you very much, really appreciate that