Factor Completely: x2 - 7x + 44
(x-7)x+44
(x-7/2)^2+127/4
wouldhnt happen to be doing imaginary numbers would you?
1/4(2x-7)^2+127/4
no
These are the three possible answers.
a) (x - 11)(x - 4) b) (x + 11)(x - 4) c) (x - 11)(x + 4) d) (x + 11)(x + 4) which one is it?
you must of typed the wrong questoin... no possible way to factor unless you go into the imaginary plane.
don't think you can factor completely
you can but it will be in terms of i... no big deal really
your right csevgf but I don't think at his level they're using I plane
how about this -(x+11)(x-4)
None of the choices given are the answer. Spcifically: a) (x-11)(x-4) The middle term becomes -15x which is not -7x b) (x+11)(x-4) The middle term becomes +7x which is not -7x c) (x-11)(x+4) The last term becomes -44 which is not +44 d) (x+11)(x+4) The middle term becomes +15x Therefore, none of the choices that were given is a solution.
Yes ^^
What i wrote makes sense though.
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