Question

solve : x^2 +y^2 = 41
x - y = 1

Answer 1

y=5,4 and x= 5,6

Answer 2

From second equation x = 1 + y
Substituting in first equation

(1 + y)^2 + y^2 = 41
1 + 2y + y^2 + y^2 = 41
2y^2 + 2y + 1 -41 = 0
2y^2 + 2y - 40 = 0

Solve this to get value of y substitute in second equation and get value of x

Answer 3

x^2+y^2=41

Answer 4

the answer is xy+2=41

Answer 5

Can u pls read your question again and rewrite the full question

Answer 6

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