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Mathematics 19 Online
OpenStudy (anonymous):

determine (f*g)(x) and (g*f)(x): f(x)=square root x+1

OpenStudy (anonymous):

The question is invalid because g(x) can be anything, since f(x) was given. if you mean that h(x) = √(x + 1), then you can infer your own functions, which should be quite obvious.

OpenStudy (anonymous):

Oops I wrote that question wrong... f(x)=sr x+1, g(x)=x+2

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