Question

how do you solve y=e^(x+2)

Answer 1

\[e ^{x}=y/(e ^{2}\]. \[x=\ln y+\ln(e ^{-2})=\ln y-2\]

Answer 2

lny = lne^(x+2)
lny = (x+2)lne
lny = x+2
x = lny -2

Answer 3

it has many solutions; you slove it by graphing the plots on a peice of paper ...