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find the vertex and the parabola: f(x)=-x^2-2x+3
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*of the parabola
the vertex is when x = -b/2a
--2/2.1 = 2/2 = 1 (1,y)... -1-2+3=0 (1,0) is the vertex
i think that typoed...
--2/2.-1 = 2/-2 = -1
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(-1,y)...-1+2+3 = 4 (-1,4)
vertex is (-1,4)
you could always write it in vertex form f(x)=-(x^2+2x)+3=-(x^2+2x+1)+3+1=-(x+1)^2+4 vertex is (-1,4)
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