Question

3x^2-5x-12=0
solve the equation check your solution
show work

Answer 1

3x^2 -9x + 4x -12 = 0
3x(x-3) +4(x-3)=0
(3x+4)(x-3)=0
hence 3x+4 = 0 so x = -4/3
and
x-3 = 0 so x =3
so x = -4/3, 3

Answer 2

3x²-5x-12=0
3x² - 9x + 4x - 12 = 0
3x (x - 3) + 4 (x - 3) = 0
(3x + 4) (x - 3) = 0
x = 3 or x = -4/3

Answer 3

(x- /3)(x+ /3)

1,36; 2,18; 4,9....

(x-9/3)(x+4/3)

(x-3)(3x+4)

x = 3; x=-4/3 correct :)