Question

How do you write the equation in standard form, then determine the vertex, axis and direction in which each parabola opens?

y^2 + 2y - 4x - 3 = 0

Answer 1

y=mx+b

Answer 2

so we want to write this in x=a(y-h)^2+k form
so solve for x
giving us
x=[y^2+2y-3]/4
x=y^2/4+y/2-3/4
x=1/4(y^2+2y)-3/4
x=1/4(y^2+2y+1)-3/4-1/4
x=1/4(y+1)^2-1

Answer 3

Thank you. My pc is acting up, so I didn't even know you messaged.

Answer 4

Thank you. My pc is acting up, so I didn't even know you messaged.