Question

Please help me to solve this equation :
(2x^3+5x^2-22x+10)/(2x-3)

Answer 1

What are you solving for? When the expression equals 0?

Answer 2

They just ask to perform the indicated operations

Answer 3

x^2 + 4x - 5 Remainder -5

Answer 4

Could you please show me the step?

Answer 5

Do you know how to long divide?

Answer 6

no, i don't know how to do it

Answer 7

A long process... Here goes.

Answer 8

2x times what is 2x^3 ... the answer is x^2 so that is what you put up first.
Once you put something on top, you multiply it by what is to the left of the 2x^3 you distribute to accomplish this.
Then draw a line under what you just wrote.

x^2
-----------------------
2x - 3 |2x^3 + 5x^2 - 22x + 10
2x^3 - 3x^2
------------

Answer 9

Then you change the signs on the bottom and add.
And then bring down the next term.

Start again... same steps.... 2x times what is 8x^2... answer 4x.. I will put that on top

x^2
-----------------------
2x - 3 |2x^3 + 5x^2 - 22x + 10
-2x^3 + 3x^2
-----------
8x^2 - 22x

Answer 10

x^2 + 4x - 5 Remainder -5
-----------------------
2x - 3 |2x^3 + 5x^2 - 22x + 10
-2x^3 + 3x^2
-----------
8x^2 - 22x
- 8x^2 + 12x
-----------
-10x + 10
+10x - 15
---------
-5

2x times what is -10x... answer -5

Answer 11

I got it...thanks so much