Question

what is the solution in the set of real numbers of the quadratic equation \[x ^{2}-3x+10=0\]

Answer 1

use quadratic formula
a=1
b=-3
c=10
\[\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\]
this gives
3 +-sqrt(-31)/2
=3/2 +- sqrt(31)/2 i