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A speedboat traveled 2 hrs with a 4 km/h current before turning around.The return trip against the same current took 3 hrs.Find the speed of the boat in still water.
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2x+2*4=3x-3*4 so x=20 km/hr x is the speed of boat
in direction of current speed of current will add to the speed of boat...but in opposite it will decrease the speed of the boat.
and the distance for both trips is equal
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