The sum of the digits of a two-digit number is 12.If the digits are reversed,the new number is 18 more than the original number.Find the original number.

Question

anonymous · Answer

x+y = 12
10y+x = 10X + y +18

anonymous · Answer

where x and y are the 2 digits

anonymous · Answer

x+y=12
x+10y=y+10x+18
x-y=2.
gives u x=7,y=5
the no is 57

anonymous · Answer

jab ek banda reply kar chuka to kyun sab zor lagate ho yaar?

anonymous · Answer

TLet the original number be 10x + (12-x)
Then on reversing it becomes
10(12-x) + x 

Atq 10(12-x) + x = 10x + (12-x) + 18

Solve this, get value of x and then get the two numbers