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factor using the difference of 2 squares 1.x^2-36 2.x^2+4 3.4x^2-25 4.y^2-1
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1.(x-6)(x+6)
\[x^2+4x+4-4x=(x+2)^2-(2\sqrt{x})^2=(x+2-2\sqrt{x})(x+2+2\sqrt{x})\]
3.(2x-5)(2x+5)
4.(y_1)(y+1)
ok so you guys are confusing me uzma its the same thing as before
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which 1?
its gunna start out as factoring out the GCF and i have to do the difference of 2 squares method, or trial and error and i dont know how to do it.
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