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Point A (–4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x = 2 is the perpendicular bisector of AB ?
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Form a point slope form equation between A (-4,1) and B(x,y)
2--4=6 therefore midpoint = 6 so length =12 -4+12=8 therefore x co ordinate = 8 x=2 is perpendicular bisector so x co ordinate has to be the same so y=1 B ( 8,1)
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