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x^6-y^6=
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???
u want the factors?
I have to solve w/special factoring
\[x^6-y^6 =(x^3)^2-(y^3)^2\]
\[= (x^3-y^3)(x^3+y^3)\]
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\[(x-y)(x^2+x y+y^2)(x+y )( x^2-x y +y^2)\]
you got it?
Yes, I'm going over this though
why do we do the (x+y)(x^2-xy+y^2) ?
factors of (x^3+y^3)
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awwwwwww....I see!
Thanks so much!
ur welcome :)
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