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equation of bisector of acute angle between lines 3x+4y+5=0 and 12x-5y-7=0 is
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u dont know this?
i dont knw my ans is nt matchng
frst make both the c +ve
multiply the second line with -1
and now as a1a2 + b1b2 is -ve
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L1/5 = -L2/13
get it??
kind of..........
oh i got it where i was wrong thanx
see when a1a2 + b1b2 is negtiv, the eqn where signs of both lines are opposite is the acute bisector
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yeah....no prob
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