Question

equation of bisector of acute angle between lines 3x+4y+5=0 and 12x-5y-7=0 is

Answer 1

u dont know this?

Answer 2

i dont knw my ans is nt matchng

Answer 3

frst make both the c +ve

Answer 4

multiply the second line with -1

Answer 5

and now as a1a2 + b1b2 is -ve

Answer 6

L1/5 = -L2/13

Answer 7

get it??

Answer 8

kind of..........

Answer 9

oh i got it where i was wrong thanx

Answer 10

see when a1a2 + b1b2 is negtiv, the eqn where signs of both lines are opposite is the acute bisector

Answer 11

yeah....no prob