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9r^2+15r+6 factored out with work
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would the solution (9r+3)(r+2) be correct
not quite 18r+3r = 21r not 15r
Let's work it out. (9r + 3)(r + 2) First: \[9r*r = 9r ^{2}\] Outside: 9r*2=18r Inside: 3*r = 3r Last: 3*2=6 \[9r ^{2}+18r + 3r + 6 = 9r^{2} + 21r + 6\]
So, not quite. As dumbcow beat me to it. :)
9*6=54 9+6=15 (9r+6)(9r+9) reduce (3r+2)(3r+3)
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ohhhh
actually i forgot you could factor out a 3 first 3(3r^2 +5r +2) =3(3r+2)(r+1)
ok lol
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