i know it seems long but it the info being given :S
please help, thanks :)

A branching plant has stems, nodes, leaves and buds.
-there are 7 leaves at each node and at each node, 2 new stems grow. at the end of each final stem, there is a bud

one plant with 3 stages of nodes has 15 stems, 7 nodes, 49 leaves and 8 buds.

qs: how do i show that the number of leaves on one of those plants with n stages of nodes there are?

a formula given is 7(2^n-1)

thanks :)

Question

i know it seems long but it the info being given :S
please help, thanks :)

A branching plant has stems, nodes, leaves and buds.
-there are 7 leaves at each node and at each node, 2 new stems grow.  at the end of each final stem, there is a bud

one plant with 3 stages of nodes has 15 stems, 7 nodes, 49 leaves and 8 buds.

qs: how do i show that the number of leaves on one of those plants with n stages of nodes there are?

a formula given is 7(2^n-1)

thanks :)

amistre64 · Answer

what is a node stage; is that like how many times it branches out?

anonymous · Answer

yes :)

amistre64 · Answer

like this right?

amistre64 · Answer

28 if im doin the formula right

anonymous · Answer

once sec. i think i have the diagram with it, but do you need it for the qs???

amistre64 · Answer

it might help

anonymous · Answer

ok, on sec.

anonymous · Answer

attachment

amistre64 · Answer

ahhh... i was wondering how they got 15 stems.... thats better.

there are 7 clusters of leaves; so 7*7=49

anonymous · Answer

but how do i show it coz i have to show it :S

amistre64 · Answer

well, use the formula...  the n=3

7[(2^n)-1]

7[(2^3)-1]

7[8-1]

7[7]

49

anonymous · Answer

oh ok,  thank you :)
medal earned

amistre64 · Answer

yay!!....im gonna sell these on ebay :)

anonymous · Answer

lol XD