Question

Solve the system of equations
x + 3y = 32
-3x + 2y = 3

Answer 1

3x+9y=64 (multiplied first by 3)
add two equations:
11y=67
y=67/11

Answer 2

oops that's incorrect

Answer 3

x + 3y = 32 Multiply this equation by 3 in order to eliminate x
-3x+2y= 3

3x +9y =96
-3x + 2y = 3

11y = 99
y = 9

x + 3(9) = 32 Substituting y=9 to find x
x + 27 =32
x = 5

Therefore, x=5 and y=9

Answer 4

3x+9y=96**
11y=99
y=9