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how does sqrt(16)^(1/2) =2 ? I don't know how to get to that answer without my calculator :)
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\[(\sqrt{16})^{1/2}\] = \[\sqrt{\sqrt{16}}\] you are basically taking the sqrt two times: \[\sqrt{16} = 4\] \[4^{1/2} = \sqrt{4}\]
\[a ^{b/c}=(\sqrt[c]{a})^{b}\]
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