Question

3y^3 (2y-5)(y+5)

Answer 1

What?

Answer 2

\[3y ^{3}\times(2y-5)(y+5) = 3y ^{3}\times(2y ^{2}+10y-5y-25)=6y ^{5}+15y ^{4}-75y ^{2}\]

Answer 3

ops the last term should be to the third not second: \[-75y ^{3}\]

Answer 4

yes that is one of the options & thank you! I didn't realize that they could be separated like this 3y3×(2y−5)(y+5) & 3y3×(2y2+10y−5y−25)