Amir pitched a baseball at an initial height of 5.9 feet with a velocity of 73.16 feet per second. About how long will it take the ball Amir pitched to hit the ground?

Question

anonymous · Answer

$$s_f=v_0t+(1/2)gt^2+5.9ft $$ since final height = 0 ft we have $$0 = 73.16t-4.9t^2+5.9$$ use quadratic equation to solve for t.

anonymous · Answer

$$g  = 32 ft/s^2$$

anonymous · Answer

so $$0 = 73.16t-32t^2+5.9$$
sorry about that
g in ft/s^2 is actually 32.17ft/s^2 correct to 2 decimal places.

anonymous · Answer

$$\ 0 = 73.16t-16t^2+5.9$$

i forgot to ake (1/2)g pr (1/2)32ft/s^2

I must be exhausted