Question

for nonzero numbers w, x, and y, if x is twice y and y is (1/3) of w, what is teh ratio of w^2 to x^2

Answer 1

2 / (1/3) = 6
6^2 = 36
therefore the ratio is 1:36

Answer 2

x = 2y and y = (1/3)w
3y = w

we have:

w^2/x^2 = (3y)^2 / (2y)^2 = 9/4 - the y^2 cancels

Answer 3

thanks