Question

how do you solve 6x^2-8x-7=0

Answer 1

use quadratic equation form
u know how to solve it?

Answer 2

( -b + - Square -b^2 - (4*a*c)): 2a

Answer 3

a=6
b=-8
c=-7

Answer 4

\[(-(-8)\pm \sqrt{-8^{2}-(4*6*(-7)})\div(2*6)\]\[(8\pm \sqrt{64+168})\div6\]\[(8\pm \sqrt{232})\div6\]\[x=(1/6)(4\pm58)\]