Question

find the factors
2x^4+16x^3+32x^2=0

Answer 1

2 x^2 (x+4)^2
x = 0, 0, -4, -4

Answer 2

i got something different, i didnt get -4 i got just 4

Answer 3

i got 2x^2(x+4)^2

Answer 4

Thats what I have.

Answer 5

Plug in -4 into the (x+4)^2, and get 0.

Answer 6

The answer you are looking for is 2x^2(x+4)^2