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use the square root property to solve the quadratic equation 7x^2-35=0 a. x= +/ - sqrt of 5 b. x= sqrt of 5 c. x= + / - sqrt 35 / 7 d…
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\[7x^{2}=35\]\[x^{2}=35/7\]\[x = \pm \sqrt{ 35/7} \]
thank you that was explained beautifuly now i understand it :)\
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