Question

who can help me with calculus??!!

Answer 1

I can

Answer 2

ok it has tpo do with integrals

Answer 3

ok

Answer 4

\[\int\limits\limits_{1}^{7} 1/\sqrt[3]{t} dt\]

Answer 5

if \[f(x)=1/\sqrt[3]{t}\]
\[F(x)=(3/2)\sqrt[3]{t}^2\]

The result is F(7) - F(1)
Calculate that for yourself

Answer 6

ok thank you!

Answer 7

hey you still there?

Answer 8

I will help you

Answer 9

ok

Answer 10

\[\int\limits_{3}^{b} 3x ^{2} dx = 37 \]

Answer 11

find the value of b?

Answer 12

\[\int\limits_{3}^{b}\]\[\int\limits_{}^{}3x ^{2}dx = 3x^{3}/3 = x^3\]

Answer 13

substituting the limits
we get
\[b^3 - 3 ^3 \]

Answer 14

now \[b^3 - 3^3 = 37 \]

Answer 15

\[b^3 =27+37\]

Answer 16

\[b^3=64 \]

Answer 17

\[ b^3 = 4^3 \]

Answer 18

so what happen to the 37?

Answer 19

b=4 is your answer

Answer 20

37 got added with 27

Answer 21

37+ 27 = 54

Answer 22

oh* 37+ 27= 64

Answer 23

ahh i get it now thnaks!

Answer 24

You may email me or skype

Answer 25

can i ask you another question? i have a final tomorrow lol

Answer 26

yeah

Answer 27

Do u use skype? so that i could instruct you

Answer 28

yes i have skype

Answer 29

Jit4won

Answer 30

call me

Answer 31

ok give me a sec

Answer 32

just added you