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Add. 7/y+4 + 5/3y I can't type it out but the 7 is over y+4, 5 is over 3y
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\[{7 \over y+4}+{5 \over 3y}={21y+5y+20 \over 3y(y+4)}={26y+20 \over 3y^3+12y}\]
Thanks, I didn't do (y+4)
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