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(1-4x^6)^2
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the answer i get is 1-16x^12
\[(a + b)^{2} = a^{2} + 2ab + b^{2}\]
Since the term is squared, you get: (1-4x^6)(1-4x^6) = 1-8x^6+16x^12 = 16x^12-8x^6+1
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