the sales force a bussiness consists 10 men and 10 women. a production unit of 7 people are choosen at ramdon. what is the prob it will include 2 men and 5 women?
there are 10C2 ways of choosing 2 men. there are 10C5 ways of choosing 5 women there are 20C7 ways of choosing 7 people from 20 people. multiply the first two and divide by the second.
what r u multoplying thou?
10c2 times 10c5 divided by 20c7
how do u do that on the calculator a reg one
105c5?
ok, 10C2 = 10*9/2! 10C5 = 10*9*8*7*6/5! 20C7 = 20*19*18*17*16*15*14/7! remember that 7! = 7*6*5*4*3*2*1, then do what dhatraditya said
so u mutlply all those?
10c2= 45
10c5= 6048
10C5 = 252
http://www.youtube.com/watch?v=XqQTXW7XfYA&feature=related http://www.mathsisfun.com/combinatorics/combinations-permutations.html http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html see all the related videos from khanacademy too for permutations and combinations.
55814400 20c7
so now what?
6048*252/55814400 is your answer
1524096
45*252/77520= 1134/7752 = 567/3876 = 189/1292
=(10C2*10C5)/(20C7)
ah, I trusted prettychickas answer than 20c7 is 55814400
wait what
what r u multuplying everything
is it a decimal?
there are 10C2 ways of choosing 2 men. there are 10C5 ways of choosing 5 women there are 20C7 ways of choosing 7 people from 20 people. multiply the first two and divide by the second (10C2*10C5)/(20C7) = 45*252/77520= 1134/7752 = 567/3876 = 189/1292
so u devide those now?
It depends, what format is required? fractions are ok, so long as they are reduced.
ok so
i dont get it i am getting a decimal
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