Question

show the algebraic inequality. show work.
Tammy has the following scores on her business law test 92,99,84,91. what score must she earn in order to an A average. and A at her univ starts at 90

Answer 1

(92+99+84+91+x)/5>=90 Where the symbol >= represents greater than or equal to and x represents the score needed

92+99+84+91+x>=(90)(5)
92+99+84+91+x>=450 Now add the numbers on the left side to get:
366+x>=450
x>=450-366
x>=84

Therefore, 84 is the lowest score needed in order to get an A average.