Question

given the equation, where is the center of the conic section? (x+1)^2/16+(y-1)^2/16=1

Answer 1

(x+1) and (y-1) are notes or clues as to where the center is. What makes these parts equal 0?

In other words;

(x+1,y-1) = (0,0)..which is the origin by the way

Answer 2

Standard equation, similar to eq of circle
(x-h)^2 + (x-k)^2= center (h,k)

Answer 3

a. (-1,1)
b. (1,-1)
c. (4,4)
d.(x.y)